c: specify static array size in function params

The C standard states:

  A declaration of a parameter as ``array of type'' shall be adjusted to ``qualified pointer to
  type'', where the type qualifiers (if any) are those specified within the [ and ] of the
  array type derivation. If the keyword static also appears within the [ and ] of the
  array type derivation, then for each call to the function, the value of the corresponding
  actual argument shall provide access to the first element of an array with at least as many
  elements as specified by the size expression.

By changing void func(int array[4]) to void func(int array[static 4]),
we automatically get the compiler checking argument sizes for us, which
is quite nice.

1 files changed, 1 insertions, 1 deletions

diff --git a/src/peer.h b/src/peer.h
index 47534a2..580d295 100644
--- a/src/peer.h
+++ b/src/peer.h
@@ -39,7 +39,7 @@ struct wireguard_peer {
 	uint64_t internal_id;
 };
 
-struct wireguard_peer *peer_create(struct wireguard_device *wg, const u8 public_key[NOISE_PUBLIC_KEY_LEN]);
+struct wireguard_peer *peer_create(struct wireguard_device *wg, const u8 public_key[static NOISE_PUBLIC_KEY_LEN]);
 
 struct wireguard_peer *peer_get(struct wireguard_peer *peer);
 void peer_put(struct wireguard_peer *peer);