c: specify static array size in function params

The C standard states:

  A declaration of a parameter as ``array of type'' shall be adjusted to ``qualified pointer to
  type'', where the type qualifiers (if any) are those specified within the [ and ] of the
  array type derivation. If the keyword static also appears within the [ and ] of the
  array type derivation, then for each call to the function, the value of the corresponding
  actual argument shall provide access to the first element of an array with at least as many
  elements as specified by the size expression.

By changing void func(int array[4]) to void func(int array[static 4]),
we automatically get the compiler checking argument sizes for us, which
is quite nice.

Signed-off-by: Jason A. Donenfeld <Jason@zx2c4.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/src/show.c b/src/show.c
index ddda6c3..3a32cb8 100644
--- a/src/show.c
+++ b/src/show.c
@@ -78,7 +78,7 @@ static void sort_peers(struct wgdevice *device)
 
 static const uint8_t zero[WG_KEY_LEN] = { 0 };
 
-static char *key(const unsigned char key[WG_KEY_LEN])
+static char *key(const unsigned char key[static WG_KEY_LEN])
 {
 	static char b64[b64_len(WG_KEY_LEN)];
 	if (!memcmp(key, zero, WG_KEY_LEN))