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/* $OpenBSD: encoding.c,v 1.1 2021/04/01 06:43:23 claudio Exp $ */
/*
* Copyright (c) 2020 Claudio Jeker <claudio@openbsd.org>
*
* Permission to use, copy, modify, and distribute this software for any
* purpose with or without fee is hereby granted, provided that the above
* copyright notice and this permission notice appear in all copies.
*
* THE SOFTWARE IS PROVIDED "AS IS" AND THE AUTHOR DISCLAIMS ALL WARRANTIES
* WITH REGARD TO THIS SOFTWARE INCLUDING ALL IMPLIED WARRANTIES OF
* MERCHANTABILITY AND FITNESS. IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR
* ANY SPECIAL, DIRECT, INDIRECT, OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES
* WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN
* ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF
* OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE.
*/
#include <err.h>
#include <limits.h>
#include <stdlib.h>
#include <string.h>
#include <openssl/evp.h>
#include "extern.h"
/*
* Decode base64 encoded string into binary buffer returned in out.
* The out buffer size is stored in outlen.
* Returns 0 on success or -1 for any errors.
*/
int
base64_decode(const unsigned char *in, unsigned char **out, size_t *outlen)
{
static EVP_ENCODE_CTX *ctx;
unsigned char *to;
size_t inlen;
int tolen;
if (ctx == NULL && (ctx = EVP_ENCODE_CTX_new()) == NULL)
err(1, "EVP_ENCODE_CTX_new");
*out = NULL;
*outlen = 0;
inlen = strlen(in);
if (inlen >= INT_MAX - 3)
return -1;
tolen = ((inlen + 3) / 4) * 3 + 1;
if ((to = malloc(tolen)) == NULL)
return -1;
EVP_DecodeInit(ctx);
if (EVP_DecodeUpdate(ctx, to, &tolen, in, inlen) == -1)
goto fail;
*outlen = tolen;
if (EVP_DecodeFinal(ctx, to + tolen, &tolen) == -1)
goto fail;
*outlen += tolen;
*out = to;
return 0;
fail:
free(to);
return -1;
}
/*
* Convert binary buffer of size dsz into an upper-case hex-string.
* Returns pointer to the newly allocated string. Function can't fail.
*/
char *
hex_encode(const unsigned char *in, size_t insz)
{
const char hex[] = "0123456789ABCDEF";
size_t i;
char *out;
if ((out = calloc(2, insz + 1)) == NULL)
err(1, NULL);
for (i = 0; i < insz; i++) {
out[i * 2] = hex[in[i] >> 4];
out[i * 2 + 1] = hex[in[i] & 0xf];
}
out[i * 2] = '\0';
return out;
}
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